I am trying to create a message with a Yes or No button. Then a window will appear with a certain message that depends on if the user clicked Yes or No. Here is my code: Right now it prints HELLO whether or not you press Yes or No. How do I get it to … Read more
You’re trying to return variable Labels of type ArtworkData instead of array, therefore this needs to be in the method signature as its return type. You need to modify your code as such: Array[] is actually an array of Array, if that makes sense.
You could define callFriend this way: Then call it as such: This code has the benefit of not generating any compiler warnings. Of course this is really just an updated version of casting from the pre-generic days and doesn’t add any additional safety.
For non-object return types, you have to assign the value to the name of your function, like this: Example usage: If the function returns an Object type, then you must use the Set keyword like this: Example usage: Note that assigning a return value to the function name does not terminate the execution of your function. If … Read more
From man bash on return [n]; Causes a function to stop executing and return the value specified by n to its caller. If n is omitted, the return status is that of the last command executed in the function body. … on exit [n]: Cause the shell to exit with a status of n. If n is omitted, the … Read more
You never give any value to your strings in main so they are empty, and thus obviously the function returns an empty string. Replace: with: Also, you have several problems in your replaceSubstring function: std::string::find returns a std::string::size_type (aka. size_t) not an int. Two differences: size_t is unsigned, and it’s not necessarily the same size as an int depending on your platform (eg. on 64 bits Linux or … Read more
Although Bash has a return statement, the only thing you can specify with it is the function’s own exit status (a value between 0 and 255, 0 meaning “success”). So return is not what you want. You might want to convert your return statement to an echo statement – that way your function output could be captured using $() braces, which seems to be exactly what you want. Here is … Read more
In C++11, this is the preferred way: That is, return by value. With C++11, std::vector has move-semantics, which means the local vector declared in your function will be moved on return and in some cases even the move can be elided by the compiler.
I got that error which cant figure out. I look over related questions but I dont give a meaning someone show me which part do I need to fix? [Error] void value not ignored as it ought to be My codes
Named tuples were added in 2.6 for this purpose. Also see os.stat for a similar builtin example. In recent versions of Python 3 (3.6+, I think), the new typing library got the NamedTuple class to make named tuples easier to create and more powerful. Inheriting from typing.NamedTuple lets you use docstrings, default values, and type annotations. Example (From the docs):