Use LocalDateTime#parse()
(or ZonedDateTime#parse()
if the string happens to contain a time zone part) to parse a String
in a certain pattern into a LocalDateTime
.
String oldstring = "2011-01-18 00:00:00.0"; LocalDateTime datetime = LocalDateTime.parse(oldstring, DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.S"));
Use LocalDateTime#format()
(or ZonedDateTime#format()
) to format a LocalDateTime
into a String
in a certain pattern.
String newstring = datetime.format(DateTimeFormatter.ofPattern("yyyy-MM-dd")); System.out.println(newstring); // 2011-01-18
Or, when you’re not on Java 8 yet, use SimpleDateFormat#parse()
to parse a String
in a certain pattern into a Date
.
String oldstring = "2011-01-18 00:00:00.0"; Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.S").parse(oldstring);
Use SimpleDateFormat#format()
to format a Date
into a String
in a certain pattern.
String newstring = new SimpleDateFormat("yyyy-MM-dd").format(date); System.out.println(newstring); // 2011-01-18
See also:
- Java string to date conversion
Update: as per your failed attempt: the patterns are case sensitive. Read the java.text.SimpleDateFormat
javadoc what the individual parts stands for. So stands for example M
for months and m
for minutes. Also, years exist of four digits yyyy
, not five yyyyy
. Look closer at the code snippets I posted here above.