printf with std::string?

It’s compiling because printf isn’t type safe, since it uses variable arguments in the C sense1. printf has no option for std::string, only a C-style string. Using something else in place of what it expects definitely won’t give you the results you want. It’s actually undefined behaviour, so anything at all could happen. The easiest way to fix this, since … Read more

Is there a printf converter to print in binary format?

Hacky but works for me: For multi-byte types You need all the extra quotes unfortunately. This approach has the efficiency risks of macros (don’t pass a function as the argument to BYTE_TO_BINARY) but avoids the memory issues and multiple invocations of strcat in some of the other proposals here.

How I can print to stderr in C?

The syntax is almost the same as printf. With printf you give the string format and its contents ie: With fprintf it is the same, except now you are also specifying the place to print to: Or in your case:

What is the printf format specifier for bool?

There is no format specifier for bool types. However, since any integral type shorter than int is promoted to int when passed down to printf()‘s variadic arguments, you can use %d: But why not: or, better: or, even better: instead?

Printing hexadecimal characters in C

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension. Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your … Read more

printf() formatting for hexadecimal

Why, when printing a number in hexadecimal as an 8 digit number with leading zeros, does %#08X not display the same result as 0x%08X? When I try to use the former, the 08 formatting flag is removed, and it doesn’t work with just 8.

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