You have your printing loop inside your reading loop. It is trying to print out all of the trip information after reading the first one in. Edit: The trouble here is that the way scanf handles single characters is kinda unintuitive next to the way it handles strings and numbers. It reads the very next … Read more
The %c conversion specifier won’t automatically skip any leading whitespace, so if there’s a stray newline in the input stream (from a previous entry, for example) the scanf call will consume it immediately. One way around the problem is to put a blank space before the conversion specifier in the format string: The blank in the format string tells scanf to … Read more
So many problems in so few lines. I probably forget some: argv[0] is the program name, not the first argument; if you want to read in a variable, you have to allocate its memory one never loops on feof, one loops on an IO function until it fails, feof then serves to determinate the reason … Read more
An array “decays” into a pointer to its first element, so scanf(“%s”, string) is equivalent to scanf(“%s”, &string[0]). On the other hand, scanf(“%s”, &string) passes a pointer-to-char[256], but it points to the same place. Then scanf, when processing the tail of its argument list, will try to pull out a char *. That’s the Right Thing when you’ve passed in string or &string[0], but when … Read more
So many problems in so few lines. I probably forget some: argv[0] is the program name, not the first argument; if you want to read in a variable, you have to allocate its memory one never loops on feof, one loops on an IO function until it fails, feof then serves to determinate the reason … Read more
There are multiple differences. Two crucial ones are: fgets() can read from any open file, but scanf() only reads standard input. fgets() reads ‘a line of text’ from a file; scanf() can be used for that but also handles conversions from string to built in numeric types. Many people will use fgets() to read a line of data and then use sscanf() to dissect it.