How to simplify Boolean expression with XOR?
If you consider that A XOR B is equivalent to (A AND ~B) OR (~A AND B) then the rest should be easy.
If you consider that A XOR B is equivalent to (A AND ~B) OR (~A AND B) then the rest should be easy.
It has to do with mutual exclusion. xor is exclusive. or is inclusive. Truth Table Comparison Note: the difference in the last case. xor is only true when either $x or $y is true, but not both (as the case for or).
In the following example, I’m trying to scan the value of boolean type of variable. When I compile in GCC, I get following warning, code: My question is, Is there any format specifier of bool in C
You could use the BIT datatype to represent boolean data. A BIT field’s value is either 1, 0, or null.
You can try Wolfram Alpha as in this example based on your input: http://www.wolframalpha.com/input/?i=((A%20OR%20B)%20AND%20(NOT%20B%20AND%20C)%20OR%20C)&t=crmtb01&f=rc