How to fix C++ error: expected unqualified-id
There should be no semicolon here: …but there should be one at the end of your class definition:
There should be no semicolon here: …but there should be one at the end of your class definition:
Try to set g++ to your system path. You can refer to this: http://stephencoakley.com/2015/01/21/guide-setting-up-a-simple-c-development-environment-on-windows
The error is clear. You can only use integral types (integer, enum, char etc. which are convertible to integral value), or any expression that evaluates to an integral type in switch statement.
Oh man, one of my pet peeves. inline is more like static or extern than a directive telling the compiler to inline your functions. extern, static, inline are linkage directives, used almost exclusively by the linker, not the compiler. It is said that inline hints to the compiler that you think the function should be … Read more
First of all, don’t use char* or char[N]. Use std::string, then everything else becomes so easy! Examples, Easy, isn’t it? Now if you need char const * for some reason, such as when you want to pass to some function, then you can do this: assuming this function is declared as: Explore std::string yourself starting … Read more
How to create timer events using C++ 11? I need something like: “Call me after 1 second from now”. Is there any library?
c is double, thus you cannot use the modulo operator %. Use fmod() instead. So change this: to this: As Slava mentioned, you could have used an int instead, like this: which wouldn’t require the use of fmod(). It’s important to understand that the modulo operator % works with ints. As πάντα ρέι mentioned, there … Read more
Your second example does not work if you send the argument by reference. Did you mean That would work, but an easier way is
I’m having trouble with the following assignment, mostly because I don’t understand how a Boolean function works. “Write a function called Divisible that takes in two numbers as parameters. Return True if the first number is evenly divisible (no remainder) by the second number. Otherwise return False. Hint: Use %” Currently what I have is: … Read more
This answer is useful 30 You can use memcpy after the allocation. I’m not aware of any syntax that lets you do this automagically. Much later edit: