I’m new to JAVA and I’m trying to read data from a .txt file. I’ve implemented a Scanner object ‘in’ Scanner in=new Scanner(“file.txt”); and then down the code a while loop to traverse through the content of the file.There are multiple rows of data in the file and in each row there are three strings … Read more
You do not necessarily have to split the line because java.util.Scanner’s default delimiter is whitespace. You can just create a new Scanner object within your while statement.
when i run following code it shows error that scanner cannot be resolved to type. i checked that jre is installed and version is 1.7 what else do i need to check ? please help.
How do I use the useDelimiter() method of the Scanner class to use both the comma (,) and the new line character (\n) as delimiters? I am parsing some text from a csv file.
You have to put file extension here
In Java I can pass a Scanner a string and then I can do handy things like, scanner.hasNext() or scanner.nextInt(), scanner.nextDouble() etc. This allows some pretty clean code for parsing a string that contains rows of numbers. How is this done in C# land? If you had a string that say had: In Java I … Read more
This has really puzzled me for a while but this is what I found in the end. When you call, sc.close() in first method, it not only closes your scanner but closes your System.in input stream as well. You can verify it by printing its status at very top of the second method as : … Read more
Alright, let’s elaborate with some simplified explanation about the Scanner class. It is a standard Oracle class which you can use by calling the import java.util.Scanner. So let’s make a basic example of the class: Now when you call Scanner input = new Scanner(System.in); you make a new object of the Scanner class (so you make a new “Scanner”) and you store … Read more
with Scanner you need to check if there is a next line with hasNextLine() so the loop becomes it’s readers that return null on EOF ofcourse in this piece of code this is dependent on whether the input is properly formatted