Java printf formatting to print items in a table or columns
I would use this:
printf
How do you format an unsigned long long int using printf?
Use the ll (el-el) long-long modifier with the u (unsigned) conversion. (Works in windows, GNU).
Two decimal places using printf( )
What you want is %.2f, not 2%f. Also, you might want to replace your %d with a %f 😉 This will output: When this number: 94.945600 is assigned to 2 dp, it will be: 94.95 What you want is %.2f, not 2%f.Also, you might want to replace your %d with a %f 😉#include <cstdio> int main() { printf(“When this number: %f is assigned to 2 dp, it … Read more
Align printf output in Java
You can try the below example. Do use ‘-‘ before the width to ensure left indentation. By default they will be right indented; which may not suit your purpose. Format String Syntax: http://docs.oracle.com/javase/7/docs/api/java/util/Formatter.html#syntax Formatting Numeric Print Output: https://docs.oracle.com/javase/tutorial/java/data/numberformat.html PS: This could go as a comment to DwB’s answer, but i still don’t have permissions to … Read more
How to display hexadecimal numbers in C?
Try: 0 – Left-pads the number with zeroes (0) instead of spaces, where padding is specified. 4 (width) – Minimum number of characters to be printed. If the value to be printed is shorter than this number, the result is right justified within this width by padding on the left with the pad character. By default this … Read more
How to repeat a char using printf?
Short answer – yes, long answer: not how you want it. You can use the %* form of printf, which accepts a variable width. And, if you use ‘0’ as your value to print, combined with the right-aligned text that’s zero padded on the left.. produces: With my tongue firmly planted in my cheek, I … Read more
printf format specifiers for uint32_t and size_t
Sounds like you’re expecting size_t to be the same as unsigned long (possibly 64 bits) when it’s actually an unsigned int (32 bits). Try using %zu in both cases. I’m not entirely certain though.
Execution of printf() and Segmentation Fault
This is due to stream buffering of stdout. Unless you do fflush(stdout) or you print a newline “\n” the output is may be buffered. In this case, it’s segfaulting before the buffer is flushed and printed. You can try this instead: or:
Does C have a string type?
C does not and never has had a native string type. By convention, the language uses arrays of char terminated with a null char, i.e., with ‘\0′. Functions and macros in the language’s standard libraries provide support for the null-terminated character arrays, e.g., strlen iterates over an array of char until it encounters a ‘\0’ … Read more
Which of sprintf/snprintf is more secure?
I wish to know which of these two options is the more secure one to use: sprintf(buff, “%.*s”, MAXLEN, name) snprintf(buff, MAXLEN, “%s”, name) My understanding is that both are same. Please suggest.