It means it’s a decimal literal, as others have said. However, the origins are probably not those suggested elsewhere in this answer. From the C# Annotated Standard (the ECMA version, not the MS version): The decimal suffix is M/m since D/d was already taken by double. Although it has been suggested that M stands for … Read more
Hmm… I can’t reproduce this: Are you sure it’s not some other part of your code normalizing the decimal value later? Just in case it’s cultural issues, try this version which shouldn’t depend on your locale at all:
From MySQL docs: Fixed-Point Types (Exact Value) – DECIMAL, NUMERIC: In standard SQL, the syntax DECIMAL(M) is equivalent to DECIMAL(M,0) So, you are converting to a number with 2 integer digits and 0 decimal digits. Try this instead:
What you want is %.2f, not 2%f. Also, you might want to replace your %d with a %f 😉 This will output: When this number: 94.945600 is assigned to 2 dp, it will be: 94.95 What you want is %.2f, not 2%f.Also, you might want to replace your %d with a %f 😉#include <cstdio> int main() { printf(“When this number: %f is assigned to 2 dp, it … Read more
As the comments mention, this could produce unpredictable results like: To get the expected result, you can use one of the other answers in this question, or as @Tadhg mentioned, you can use decimal.Decimal as the jump argument. Make sure to initialize it with a string rather than a float. Or even: And then: [editor’s not: if you only … Read more
If you want the result as the nearest binary floating point number use float: If you want the result stored exactly use Decimal instead of float:
Use <iomanip>‘s std::hex. If you print, just send it to std::cout, if not, then use std::stringstream You can prepend the first << with << “0x” or whatever you like if you wish. Other manips of interest are std::oct (octal) and std::dec (back to decimal). One problem you may encounter is the fact that this produces … Read more
I have these two variables Then I did this expression but I end up with 27.0. In fact I have many other variables and when I use them in the expression I always get a 0 in the tenth’s place.
float and double are floating binary point types. In other words, they represent a number like this: The binary number and the location of the binary point are both encoded within the value. decimal is a floating decimal point type. In other words, they represent a number like this: Again, the number and the location of the decimal point are both encoded within the value – that’s … Read more
float and double are floating binary point types. In other words, they represent a number like this: The binary number and the location of the binary point are both encoded within the value. decimal is a floating decimal point type. In other words, they represent a number like this: Again, the number and the location of the decimal point are both encoded within the value – that’s … Read more