Try this instead:
function test_args() { Write-Host "here's arg 0: $($args[0])" Write-Host "here's arg 1: $($args[1])" } test_args foo bar
Note that it is $args
and not $arg
. Also when you use a PowerShell variable in a string, PowerShell only substitutes the variable’s value. You can’t directly use an expression like $args[0]
. However, you can put the expression within a $()
sub-expression group inside a double-
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