Get single item from cURL plugin API call inside bash [closed]

Since it seems the API is closed source and there may not be a way to get only a single option then the only other option is parsing the response.

I hear jq is the way to go for parsing JSON within the shell, but I don’t want to add dependencies and grep seems to have done the job:
curl -v -d 'action=plugin_information&request[slug]=custom-comment-links' https://api.wordpress.org/plugins/info/1.1/ --stderr - | grep -o '"last_updated":"[^"]*' | grep -o '[^"]*$'

You can replace last_updated with anything you’d like 🙂