The modulo operator in C will give the remainder that is left over when one number is divided by another. For example, 23 % 4 will result in 3 since 23 is not evenly divisible by 4, and a remainder of 3 is left over.
If you want to output whether or not a number is divisible by 4, you need to output something other than just the mod result. Essentially, if mod = 0 than you know that one number is divisible by another.
If you want to output whether or not the number is divisible by 4, I would suggest creating a new character that is set to “y” (yes) or “n” (no) depending on the result of the mod operation. Below is one possible implementation to generate a more meaningful output:
#include <stdio.h> #include <ctype.h> #include <math.h> int main() { int my_input[] = {23, 22, 21, 20, 19, 18}; int n, mod; char is_divisible; int nbr_items = sizeof(my_input) / sizeof(my_input[0]); for (n = 0; n < nbr_items; n++) { mod = my_input[n] % 4; is_divisible = (mod == 0) ? 'y' : 'n'; printf("%d modulo %d --> %c\n", my_input[n], 4, is_divisible); } }
This will give the following:
23 modulo 4 --> n 22 modulo 4 --> n 21 modulo 4 --> n 20 modulo 4 --> y 19 modulo 4 --> n 18 modulo 4 --> n