Get a substring of a char*
Job done 🙂
Job done 🙂
Because of how numbers are stored. Signed numbers are stored using something called “two’s complement notation”. Remember all variables have a certain amount of bits. If the most significant one of them, the one on the left, is a 0, then the number is non-negative (i.e., positive or zero), and the rest of the bits … Read more
The conio.h header is specific to Turbo C, which predates the earliest C standard by several years. It contains routines that are specific to the DOS command line. One function here that’s frequently used is getch, which allows reading one character at a time without having to press the Enter key. It also contains gotoxy which allows placing … Read more
You can use GCC on Windows by downloading MingW (discontinued) or its successor Mingw-w64.
Depends on what you want to do: to read the value as an ascii code, you can write to convert the character ‘0’ -> 0, ‘1’ -> 1, etc, you can write Explanation:a – ‘0’ is equivalent to ((int)a) – ((int)’0′), which means the ascii values of the characters are subtracted from each other. Since 0 comes directly before 1 in the ascii … Read more
Will result always be the floor of the division? What is the defined behavior? Not quite. It rounds toward 0, rather than flooring. 6.5.5 Multiplicative operators 6 When integers are divided, the result of the / operator is the algebraic quotient with any fractional part discarded.88) If the quotient a/b is representable, the expression (a/b)*b … Read more
Use -lpthread as the last compiler flag. example: gcc -o sample sample.c -lpthread
If you don’t want to change the strings, then you could simply do When you do it like this you will allocate an array of two pointers to const char. These pointers will then be set to the addresses of the static strings “blah” and “hmm”. If you do want to be able to change the actual string content, … Read more
The declaration and initialization declares a pointer array and make it point to a constant array of 31 characters. The declaration and initialization declares an array of characters, containing 31 characters. And yes, the size of the arrays is 31, as it includes the terminating ‘\0’ character. Laid out in memory, it will be something like this for the … Read more
You should provide output file name after -o option. In your case runexp.o is treated as output file name, not input object file and thus your main function is undefined.