I have a problem when try to select data from a table filtering by date. For example: The Oracle Error is: Probably the source data of table is corrupted, in this case: How can i solve this problem? Can I change this dates for null? The results of this select, select * from nls_session_parameters; , is:
In C++ 11 you can use std::chrono::system_clock::now() Example (copied from en.cppreference.com): This should print something like this:
The Date object will do what you want – construct one for each date, then compare them using the >, <, <= or >=. The ==, !=, ===, and !== operators require you to use date.getTime() as in to be clear just checking for equality directly with the date objects won’t work I suggest you use drop-downs or some similar constrained form of date entry rather than text boxes, … Read more
Replace with because there is no default constructor for Timestamp, or you can do it with the method:
Altered piece of code I often use:
Use LocalDateTime#parse() (or ZonedDateTime#parse() if the string happens to contain a time zone part) to parse a String in a certain pattern into a LocalDateTime. Use LocalDateTime#format() (or ZonedDateTime#format()) to format a LocalDateTime into a String in a certain pattern. Or, when you’re not on Java 8 yet, use SimpleDateFormat#parse() to parse a String in a certain pattern into a Date. Use SimpleDateFormat#format() to format a Date into a String in a certain pattern. See also: Java string to date … Read more
That’s the hard way, and those java.util.Date setter methods have been deprecated since Java 1.1 (1997). Moreover, the whole java.util.Date class was de-facto deprecated (discommended) since introduction of java.time API in Java 8 (2014). Simply format the date using DateTimeFormatter with a pattern matching the input string (the tutorial is available here). In your specific case of “January 2, 2010” as the input … Read more
Use new Date() to generate a new Date object containing the current date and time. Expand snippet This will give you today’s date in the format of mm/dd/yyyy. Simply change today = mm +’/’+ dd +’/’+ yyyy; to whatever format you wish.
For custom-delimited date formats, you have to pull out the date (or time) components from a DateTimeFormat object (which is part of the ECMAScript Internationalization API), and then manually create a string with the delimiters you want. To do this, you can use DateTimeFormat#formatToParts. You could destructure the array, but that is not ideal, as … Read more