keyword-argument - Read For Learn

Why am I getting this unexpected keyword argument TypeError?

When passing kwargs into a function, it expects to find the exact variable name in the list. If instead your dictionary keys were stringa, integera, and floata the function would work without problem. So you either need to change your function variable names or change the key names in your dictionary to get this to work

What is the purpose and use of **kwargs? [duplicate]

You can use **kwargs to let your functions take an arbitrary number of keyword arguments (“kwargs” means “keyword arguments”): You can also use the **kwargs syntax when calling functions by constructing a dictionary of keyword arguments and passing it to your function: The Python Tutorial contains a good explanation of how it works, along with … Read more

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