MIPS assembly for a simple for loop
Your loop goes from 0 to 14, so your bgt instruction should be: bgt $t0,14,exit I think. .
mips
MIPS – Fetch address not aligned on word boundary
I’m pretty new to assembly programming and programming in general and I’m doing my best to learn. I’ve been having trouble storing inputs to variables, can you help me please? The problem seems to occur when I load the addresses of n1 and n2, or something like that. I have tried looking at similar problems … Read more
Converting a C program to MIPS
Currently you’re generating code for x86-64 – you need to select a MIPS compiler from the popup menu above the assembly pane: After you’ve done that you’ll probably see generated code like this: Note that the compiler has optimised away some of the redundant operations in the original C code. If you want to see an … Read more
MIPS fetch address not aligned on word boundary, used .align 4, still no go
The problem with the code is, that you’re not using the address where the size is stored but the size itself: Here you load the address into A0 and the size (7) into A1: Here you load the first word stored at your array (that will load a 10). This is not what you’ve intended. … Read more
MIPS: lw (load word) instruction
They are not the same, although in some circumstances they will behave alike. The format of the lw instruction is as follows: where RegDest and RegSource are MIPS registers, and Offset is an immediate. It means, load into register RegDest the word contained in the address resulting from adding the contents of register RegSource and the Offset … Read more
MIPS architecture syscall instruction
What is the role of syscall instruction in MIPS?
Understanding how `lw` and `sw` actually work in a MIPS program
lw (load word) loads a word from memory to a register. $2 is the destination register and $4 the address register. And the source of information is the memory. 4 is an offset that is added (not multiplied) to the address register. This kind of memory access is called based addressing and is it quite … Read more
Why shift a bit using sll and such in MIPs Assembly?
its pretty much just shifting all the bits left by 1 The example they showed was a shift by 1 bit. The sll instruction isn’t limited to just shifting by 1 bit; you can specify a shift amount in the range 0..31 (a shift by 0 might seem useless, but SLL $zero, $zero, 0 is used to encode a NOP on … Read more