You need the sleep method of the Thread class. public static void sleep (long time) Causes the thread which sent this message to sleep for the given interval of time (given in milliseconds). The precision is not guaranteed – the Thread may sleep more or less than requested. Parameters time The time to sleep in … Read more
Besides calling omp_get_num_threads() outside of the parallel region in your case, calling omp_set_num_threads() still doesn’t guarantee that the OpenMP runtime will use exactly the specified number of threads. omp_set_num_threads() is used to override the value of the environment variable OMP_NUM_THREADS and they both control the upper limit of the size of the thread team that … Read more
I can see five options available: 1. Thread.Join As with Mitch’s answer. But this will block your UI thread, however you get a Timeout built in for you. 2. Use a WaitHandle ManualResetEvent is a WaitHandle as jrista suggested. One thing to note is if you want to wait for multiple threads: WaitHandle.WaitAll() won’t work … Read more
Add using Declare Background Worker: Subscribe to events: Implement two methods: Run worker async whenever your need. Track progress (optional, but often useful)a) subscribe to ProgressChanged event and use ReportProgress(Int32) in DoWorkb) set worker.WorkerReportsProgress = true; (credits to @zagy)
Thread has a method that does that for you join which will block until the thread has finished executing.
Thread is a lower-level concept: if you’re directly starting a thread, you know it will be a separate thread, rather than executing on the thread pool etc. Task is more than just an abstraction of “where to run some code” though – it’s really just “the promise of a result in the future”. So as … Read more
taken from : Android UI : Fixing skipped frames Anyone who begins developing android application sees this message on logcat “Choreographer(abc): Skipped xx frames! The application may be doing too much work on its main thread.” So what does it actually means, why should you be concerned and how to solve it. What this means is that your … Read more
Platform.setImplicitExit(false); solved my problem. I think they changed the implementation in JavaFX 8, so the same code that works without any issue in JavaFX 2 gives the not an fx application thread error there.
Is it possible that the serverSocket is being closed from another thread? That will cause this exception.
This is wrong: The problem is, what’s going to wake this thread up? That is to say, how do you guarantee that the other thread won’t call foo.notify() before the first thread calls foo.wait()? That’s important because the foo object will not remember that it was notified if the notify call happens first. If there’s … Read more