Sql Server equivalent of a COUNTIF aggregate function
You could use a SUM (not COUNT!) combined with a CASE statement, like this: Note: in my own test NULLs were not an issue, though this can be environment dependent. You could handle nulls such as:
sql-server-2005
Measure the time it takes to execute a t-sql query
One simplistic approach to measuring the “elapsed time” between events is to just grab the current date and time. In SQL Server Management Studio To calculate elapsed times, you could grab those date values into variables, and use the DATEDIFF function: That’s just one approach. You can also get elapsed times for queries using SQL … Read more
INSERT statement conflicted with the FOREIGN KEY constraint – SQL Server
In your table dbo.Sup_Item_Cat, it has a foreign key reference to another table. The way a FK works is it cannot have a value in that column that is not also in the primary key column of the referenced table. If you have SQL Server Management Studio, open it up and sp_help ‘dbo.Sup_Item_Cat‘. See which column that FK … Read more
INSERT statement conflicted with the FOREIGN KEY constraint – SQL Server
In your table dbo.Sup_Item_Cat, it has a foreign key reference to another table. The way a FK works is it cannot have a value in that column that is not also in the primary key column of the referenced table. If you have SQL Server Management Studio, open it up and sp_help ‘dbo.Sup_Item_Cat‘. See which column that FK … Read more
How can I do an UPDATE statement with JOIN in SQL Server?
Syntax strictly depends on which SQL DBMS you’re using. Here are some ways to do it in ANSI/ISO (aka should work on any SQL DBMS), MySQL, SQL Server, and Oracle. Be advised that my suggested ANSI/ISO method will typically be much slower than the other two methods, but if you’re using a SQL DBMS other … Read more
SQL query to select dates between two dates
you should put those two dates between single quotes like.. or can use keep in mind that the first date is inclusive, but the second is exclusive, as it effectively is ‘2011/02/27 00:00:00’
Selecting COUNT(*) with DISTINCT
Count all the DISTINCT program names by program type and push number DISTINCT COUNT(*) will return a row for each unique count. What you want is COUNT(DISTINCT <expression>): evaluates expression for each row in a group and returns the number of unique, non-null values.