Will Arrays.sort() increase time complexity and space time complexity?

I am assuming you are talking about Java here. So the loop will cost O(n) time, my question is that will Arrays.sort() cost more time? Yes, Arrays.sort(int[]) in all Java standard library implementations that I know, is an example of a comparison-based sort and thus must have worst-case complexity Ω(n log n). In particular, Oracle Java 7 uses … Read more

When will the worst case of Merge Sort occur?

The worst case of merge sort will be the one where merge sort will have to do maximum number of comparisons. So I will try building the worst case in bottom up manner: Suppose the array in final step after sorting is {0,1,2,3,4,5,6,7} For worst case the array before this step must be {0,2,4,6,1,3,5,7} because here left subarray={0,2,4,6} and right … Read more

Understanding Time complexity calculation for Dijkstra Algorithm

Dijkstra’s shortest path algorithm is O(ElogV) where: V is the number of vertices E is the total number of edges Your analysis is correct, but your symbols have different meanings! You say the algorithm is O(VElogV) where: V is the number of vertices E is the maximum number of edges attached to a single node. Let’s rename your E to N. So one analysis says O(ElogV) and another … Read more

What does O(log n) mean exactly?

The most common attributes of logarithmic running-time function are that: the choice of the next element on which to perform some action is one of several possibilities, and only one will need to be chosen. or the elements on which the action is performed are digits of n This is why, for example, looking up … Read more

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