The AXF file is an object file format generated by ARM’s RealView compiler (also part of Keil’s ARM-MDK) and contains both object code and debug information. In the debugger, while just the object code is loaded on the target itself, both the code and the debug information are loaded in the development host’s memory. When … Read more
This is due to stream buffering of stdout. Unless you do fflush(stdout) or you print a newline “\n” the output is may be buffered. In this case, it’s segfaulting before the buffer is flushed and printed. You can try this instead: or:
I need to input coordinates into an array until EOF is encountered, but something is wrong in my code. I used ctrl+Z, ctrl+D
You have to put ; behind the struct declaration:
C does not and never has had a native string type. By convention, the language uses arrays of char terminated with a null char, i.e., with ‘\0′. Functions and macros in the language’s standard libraries provide support for the null-terminated character arrays, e.g., strlen iterates over an array of char until it encounters a ‘\0’ … Read more
I wish to know which of these two options is the more secure one to use: sprintf(buff, “%.*s”, MAXLEN, name) snprintf(buff, MAXLEN, “%s”, name) My understanding is that both are same. Please suggest.
I recommend @Jens Gustedt hexadecimal solution: use %a. OP wants “print with maximum precision (or at least to the most significant decimal)”. A simple example would be to print one seventh as in: But let’s dig deeper … Mathematically, the answer is “0.142857 142857 142857 …”, but we are using finite precision floating point numbers. … Read more
Since you’re on an embedded platform, it’s quite possible that you don’t have the full range of capabilities from the printf()-style functions. Assuming you have floats at all (still not necessarily a given for embedded stuff), you can emulate it with something like: You’ll need to restrict how many characters come after the decimal based … Read more
You are attempting to link your project in such a way that the target of a relative addressing scheme is further away than can be supported with the 32-bit displacement of the chosen relative addressing mode. This could be because the current project is larger, because it is linking object files in a different order, … Read more
It’s probably: This is a common idiom for zeroing a register on x86. This would correspond with i = 0 in the C code. If you are curious “but why ?” the short answer is that the xor instruction is fewer bytes than mov $0, %ebx. The long answer includes other subtle reasons. I am … Read more