MySQL WHERE IN ()

Your query translates to It will only return the results that match it. One way of solving it avoiding the complexity would be, chaning the datatype to SET. Then you could use, FIND_IN_SET

Oracle Apex column link from LOV values

I’m mostly used to Apex 4.1, but this approach should work. You don’t need an LOV. Your report query should include both the MAST_ID and the TASK_NAME columns. Hide the TASK_NAME column and set MAST_ID as the linking column. If you set the Link Text (under Column Link) to #TASK_NAME#, you should get the desired result. Display As should be left at the default (Display as Text etc).

Database sharding vs partitioning

Partitioning is more a generic term for dividing data across tables or databases. Sharding is one specific type of partitioning, part of what is called horizontal partitioning. Here you replicate the schema across (typically) multiple instances or servers, using some kind of logic or identifier to know which instance or server to look for the … Read more

mysql Foreign key constraint is incorrectly formed error

I ran into this same problem with HeidiSQL. The error you receive is very cryptic. My problem ended up being that the foreign key column and the referencing column were not of the same type or length. The foreign key column was SMALLINT(5) UNSIGNED and the referenced column was INT(10) UNSIGNED. Once I made them both the same … Read more

SQL – HAVING vs. WHERE

WHERE clause introduces a condition on individual rows; HAVING clause introduces a condition on aggregations, i.e. results of selection where a single result, such as count, average, min, max, or sum, has been produced from multiple rows. Your query calls for a second kind of condition (i.e. a condition on an aggregation) hence HAVING works correctly. As a rule of thumb, use WHERE before GROUP BY and HAVING after GROUP BY. … Read more