No, this is not safe. You shouldn’t make any changes to files within a plugin’s directory, all of those changes may be overridden. If you want to change a translation, you can use a plugin such as Loco Translate or use the gettext filter.
Well, I found the following solution: $args = array( ‘category’ => array( ‘category_slug’ ) // or ‘term_taxonomy_id’ => 4 i.e. category ID ); foreach( wc_get_products($args) as $product ){ foreach( $product->get_attributes() as $attr_name => $attr ){ echo wc_attribute_label( $attr_name ); // attr label // or get_taxonomy( $attr_name )->labels->singular_name; foreach( $attr->get_terms() as $term ){ echo $term->name; } … Read more
The woocommerce_form_field() is a pluggable function, defined as follows: if ( ! function_exists( ‘woocommerce_form_field’ ) ) { /** * Outputs a checkout/address form field. * * @param string $key Key. * @param mixed $args Arguments. * @param string $value (default: null). * @return string */ function woocommerce_form_field( $key, $args, $value = null ) { … … Read more
You need to unhook the function from that action specifically: remove_action( ‘woocommerce_review_before_comment_meta’, ‘woocommerce_review_display_rating’, 10 ); (e.g. look for the opposite add_action() line in includes/wc-template-hooks.php) You’ll also need to make sure that this is run after WooCommerce has loaded and added the action you’re about to remove, e.g. place this in a plugins_loaded hook: function unhook_display_rating() … Read more
Almost one year late, but this question might still get visitors: You trigger the click, but the button doesn’t have enough time to become enabled, so that is why, by the time you click the second time the button becomes enabled. Remove the “disabled” propriety before triggering the click: <script> jQuery(‘div.woocommerce’).on(‘change’, ‘.qty’, function(){ jQuery(“[name=”update_cart”]”).prop(“disabled”, false); … Read more
You’re close – just need to tweak your arguments: <?php echo get_user_meta( $customer_id, ‘billing_phone’, true ) ?> Just make sure $customer_id is the ID of the user – you probably want get_current_user_id() instead.
I was stuck on a very similar problem. I couldn’t find anything in the woocommerce code that would let you directly look up the parent product from the variation sku. But, as product variations are stored in the wp_posts table with the type product_variation, and the SKUs are stored in the wp_post_meta table, it’s easy … Read more
That should be relatively easy. You can create a specific user role for your staff and then lock them out of the Orders page and any other admin page you deem confidential.
if ( ! empty( $_FILES[‘muti_files’] ) ) { $files = $_FILES[‘muti_files’]; foreach ($files[‘name’] as $key => $value){ if ($files[‘name’][$key]){ $file = array( ‘name’ => $files[‘name’][$key], ‘type’ => $files[‘type’][$key], ‘tmp_name’ => $files[‘tmp_name’][$key], ‘error’ => $files[‘error’][$key], ‘size’ => $files[‘size’][$key] ); } $_FILES = array(“muti_files” => $file); $i=1; foreach ($_FILES as $file => $array) { if ($_FILES[$file][‘error’] !== … Read more
Another option would be to use the current_screen hook add_action( ‘current_screen’, ‘my_admin_listing_custom_styles’ ); function my_admin_listing_custom_styles() { $current_screen = get_current_screen(); if( ‘edit’ == $current_screen->base && ‘product’ == $current_screen->post_type) { // Run some code, only on the admin products listing page for e.x add css style ?> <style type=”text/css”> a.row-title {font-size: 18px !important;} </style> <?php } }