Using pointer to char array, values in that array can be accessed?

When you want to access an element, you have to first dereference your pointer, and then index the element you want (which is also dereferncing). i.e. you need to do:

printf("\nvalue:%c", (*ptr)[0]); , which is the same as *((*ptr)+0)

Note that working with pointer to arrays are not very common in C. instead, one just use a pointer to the first element in an array, and either deal with the length as a separate element, or place a senitel value at the end of the array, so one can learn when the array ends, e.g.

char arr[5] = {'a','b','c','d','e',0}; 
char *ptr = arr; //same as char *ptr = &arr[0]

printf("\nvalue:%c", ptr[0]);