C pointers and arrays: [Warning] assignment makes pointer from integer without a cast

In this case a[4] is the 5th integer in the array aap is a pointer to integer, so you are assigning an integer to a pointer and that’s the warning.
So ap now holds 45 and when you try to de-reference it (by doing *ap) you are trying to access a memory at address 45, which is an invalid address, so your program crashes.

You should do ap = &(a[4]); or ap = a + 4;

In c array names decays to pointer, so a points to the 1st element of the array.
In this way, a is equivalent to &(a[0]).

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