Why lookup in a Binary Search Tree is O(log(n))?

I can see how, when looking up a value in a BST we leave half the tree everytime we compare a node with the value we are looking for.

However I fail to see why the time complexity is O(log(n)). So, my question is:

If we have a tree of N elements, why the time complexity of looking up the tree and check if a particular value exists is O(log(n)), how do we get that?

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