putting wp_query data into html table

Here is what is happening with your code:

  1. query_posts uses the global variable wp_query. It always
    overwrites that variable, which is why you should not use
    query_posts
    pretty much ever.
  2. Your first query_posts clobbers the original $wp_query data.
  3. You start the Loop
  4. The first thing you do in that loop is reset $wp_query to the
    original query. Now the $wp_query global has different data that
    it had when the loop started.
  5. You then clobber $wp_query yet again
  6. And start a new loop
  7. And then reset the query again.

In other words, your data is overwritten and out of sync is several different ways. The fix is to not use query_posts. Use a new WP_Query object instead.

 $outer = new WP_Query( array ( 'tag' => 'female', 'posts_per_page' => -1 ) );
 if ($outer->have_posts()) {
   while ( $outer->have_posts() ) {
     $outer->the_post();
     // ...

The rest of your problem is really a PHP/HTML one, but here is a rough outline. What you need to do is iterate over both arrays at once.

$args = array ( 'post_type' => 'post', 'posts_per_page' => -1 );
$female_query = new WP_Query( $args );

$args = array ( 'post_type' => 'page', 'posts_per_page' => -1 );
$male_query = new WP_Query( $args );

$count = max($female_query->found_posts,$male_query->found_posts);
var_dump($count);

echo '<table>';
for ($i = 0; $i < $count; $i++) {
  echo '<tr>';
    echo '<td>';
      echo $i;
    echo '<td>';
    echo '<td>';
      if (isset($female_query->posts[$i])) {
        echo $female_query->posts[$i]->post_title;
      }
    echo '<td>';
    echo '<td>';
      if (isset($male_query->posts[$i])) {
        echo $male_query->posts[$i]->post_title;
      }
    echo '<td>';
  echo '</tr>';
}
echo '</table>';

$post isn’t set in my code. This is a non-standard Loop because you need data from two queries at once. To get the meta data use $female_query->posts[$i]->ID instead of $post->ID or pass it through setup_postdatasetup_postdata($female_query->posts[$i])— though that is probably overkill for this circumstance.

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