# Calculate average in java

Just some minor modification to your code will do (with some var renaming for clarity) :

```double sum = 0; //average will have decimal point

for(int i=0; i < args.length; i++){
//parse string to double, note that this might fail if you encounter a non-numeric string
//Note that we could also do Integer.valueOf( args[i] ) but this is more flexible
sum += Double.valueOf( args[i] );
}

double average = sum/args.length;

System.out.println(average );

```

Note that the loop can also be simplified:

```for(String arg : args){
sum += Double.valueOf( arg );
}

```

Edit: the OP seems to want to use the `args` array. This seems to be a String array, thus updated the answer accordingly.

Update:

As zoxqoj correctly pointed out, integer/double overflow is not taken care of in the code above. Although I assume the input values will be small enough to not have that problem, here’s a snippet to use for really large input values:

```BigDecimal sum = BigDecimal.ZERO;
for(String arg : args){
sum = sum.add( new BigDecimal( arg ) );
}

```

This approach has several advantages (despite being somewhat slower, so don’t use it for time critical operations):

• Precision is kept, with double you will gradually loose precision with the number of math operations (or not get exact precision at all, depending on the numbers)
• The probability of overflow is practically eliminated. Note however, that a `BigDecimal` might be bigger than what fits into a `double` or `long`.

```int values[] = { 23, 1, 5, 78, 22, 4};