As the other answer by horseshoe correctly suggests, you will have to use a loop to calculate variance otherwise the statement
var = ((Array[n] – mean) * (Array[n] – mean)) / numPoints;
will just consider a single element from the array.
Just improved horseshoe’s suggested code:
var = 0; for( n = 0; n < numPoints; n++ ) { var += (Array[n] - mean) * (Array[n] - mean); } var /= numPoints; sd = sqrt(var);
Your sum works fine even without using loop because you are using accumulate function which already has a loop inside it, but which is not evident in the code, take a look at the equivalent behavior of accumulate for a clear understanding of what it is doing.
Note: X ?= Y
is short for X = X ? Y
where ?
can be any operator. Also you can use pow(Array[n] - mean, 2)
to take the square instead of multiplying it by itself making it more tidy.