I’ve been trying to run this function and the “non-numeric argument to binary operator” pops up. I’ve seen quite a few questions similar to mine, yet I still can’t figure out what is the issue with my code.
TakeOneIndStep <- function(Itl, N){ # Itl is a vector foo <- ListMaintenance(Itl, N) # is a vector of same length as Itl. Displays the coordinates of coalesced walks. incrm <- sample(c(-1, 0, 1), size = length(Itl), replace = T, prob = c(0.25, 0.5, 0.25)) for (j in 1:length(Itl)){ if(Itl[j] %in% foo){ Itl[j] <- (Itl[j] + incrm[j]) %% N }else{ Itl[j] <- "H" # H is a "placeholder", just to indicate that that particular chain has coalesced and no longer is updated. } } return(Itl) }
The error happens on the sixth line Itl[j] <- (Itl[j] + incrm[j]) %% N
.
The code for the auxiliary functions:
ListMaintenance <- function(Temp, N){ # Temp is a vector rez <- CheckCoalescence(Temp) fubar <- vector() for(i in 1:length(rez)){ for(x in 0:(N-1)){if (x %in% rez[[i]]){fubar[x] <- min(rez[[i]])} } } return(fubar) # output is a vector. Coordinates with the same value have the index of the smallest occurrence. } CheckCoalescence <- function(Pts){ mar <- unname(split(seq_along(Pts), Pts)) return(mar) }
On the big picture, I’m trying to simulate a random walk process with more than two different starting points. So the argument Itl
would be the values of each walk at time (t-1), and this function will recursively update these values.
For practical purpose, I tried to test the function with A <- c(0, 2, 3, 2, 6)
and TakeOneIndStep(A, N = 9)
In this case, A
is just an arbitrary vector. There’s more code to simulate the walk, but I just presented the part that is causing the error.