This can be done without regex:
>>> string = "Special $#! characters spaces 888323" >>> ''.join(e for e in string if e.isalnum()) 'Specialcharactersspaces888323'
You can use str.isalnum:
S.isalnum() -> bool Return True if all characters in S are alphanumeric and there is at least one character in S, False otherwise.
If you insist on using regex, other solutions will do fine. However note that if it can be done without using a regular expression, that’s the best way to go about it.
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