Are all statements also expressions? “Wherever JavaScript expects a statement, you can also write an expression. Such a statement is called an expression statement. The reverse does not hold: you cannot write a statement where JavaScript expects an expression. For example, an if statement cannot become the argument of a function.” This is comes from … Read more
The conditional operator is an expression, not a statement, that means it cannot stand alone, as the result has to be used somehow. In your code, you don’t use the result, but try to produce side effects instead. Depending on the condition before the ? the operator returns the result of either the first or … Read more
Expressions only contain identifiers, literals and operators, where operators include arithmetic and boolean operators, the function call operator () the subscription operator [] and similar, and can be reduced to some kind of “value”, which can be any Python object. Examples: yield 7 Statements (see 1, 2), on the other hand, are everything that can … Read more
If you consider that A XOR B is equivalent to (A AND ~B) OR (~A AND B) then the rest should be easy.
Square brackets are meant for character class, and you’re actually trying to match any one of: s, |, s (again), e, a, s (again), o and n. Use parentheses instead for grouping: or non-capturing group: Note: Non-capture groups tell the engine that it doesn’t need to store the match, while the other one (capturing group does). For small stuff, either works, for ‘heavy duty’ stuff, you … Read more
The error is because you can’t assign an array that way, that only works to initialize it. So applying this to your specific example: or you could use memset the same way, but instead of sizeof(int) you need size of your structure. That doesn’t always work… but given your structure, it will.
Cause of this error -You are trying to pass a primitive object into a generic type declaration whereas generic types always expect a Wrapper Class object. So please use ‘Boolean’ instead of ‘boolean’ in your code i.e. ‘B’ in caps.
Square brackets are meant for character class, and you’re actually trying to match any one of: s, |, s (again), e, a, s (again), o and n. Use parentheses instead for grouping: or non-capturing group: Note: Non-capture groups tell the engine that it doesn’t need to store the match, while the other one (capturing group does). For small stuff, either works, for ‘heavy duty’ stuff, you … Read more
I have this regex: I tested this with the following regex tool link Can you please tell me how to do to accept and space? Accept eg: John Smith Thanks in advance!