C++ – No appropriate default constructor available

In contrast to C#, this declaration; …is an instantiation of the type Player, which means that by the time you’re assigning it inside the constructor, it has already been constructed without a parameter. What you need to do is to tell the class how to initialize player in what is called an initializer list that you append to the constructor … Read more

Very basic inheritance: error: expected class-name before ‘{’ token

I’m trying to learn c++ and I’ve stumbled upon a error while trying to figuring out inheritance. Compiling: daughter.cpp In file included from /home/jonas/kodning/testing/daughter.cpp:1: /home/jonas/kodning/testing/daughter.h:6: error: expected class-name before ‘{’ token Process terminated with status 1 (0 minutes, 0 seconds) 1 errors, 0 warnings My files: main.cpp: mother.cpp: mother.h: daughter.h: and daughter.cpp: What I want … Read more

Why is inherited member not allowed?

You have to declare the over-ridden functions as part of your class definition Note that the use of virtual here is optional. As n.m. noted, you should also include a virtual destructor in Shape. You may also want to make its virtual functions pure virtual (based on your comment about Shape being abstract)

super() fails with error: TypeError “argument 1 must be type, not classobj” when parent does not inherit from object

Your problem is that class B is not declared as a “new-style” class. Change it like so: and it will work. super() and all subclass/superclass stuff only works with new-style classes. I recommend you get in the habit of always typing that (object) on any class definition to make sure it is a new-style class. Old-style classes (also … Read more

What is object slicing?

“Slicing” is where you assign an object of a derived class to an instance of a base class, thereby losing part of the information – some of it is “sliced” away. For example, So an object of type B has two data members, foo and bar. Then if you were to write this: Then the information in b about member bar is lost in a.

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Base class constructors are automatically called for you if they have no argument. If you want to call a superclass constructor with an argument, you must use the subclass’s constructor initialization list. Unlike Java, C++ supports multiple inheritance (for better or worse), so the base class must be referred to by name, rather than “super()”. … Read more