I am trying to make a function that returns double the integer number that I will pass to it. I am getting the following error message with my code: declaration of ‘int x’ shadows a parameter int x; “ Here is my code:
See the Integer class and the static parseInt() method: http://developer.android.com/reference/java/lang/Integer.html You will need to catch NumberFormatException though in case of problems whilst parsing, so:
Note that if someApi() returns type Integer the only possibilities of something returned are: an Integer null In which case you can:
num will always contain an integer because it’s an int. The real problem with your code is that you don’t check the scanf return value. scanf returns the number of successfully read items, so in this case it must return 1 for valid values. If not, an invalid integer value was entered and the num … Read more
They are completely equivalent when used with printf(). Personally, I prefer %d, it’s used more often (should I say “it’s the idiomatic conversion specifier for int“?). (One difference between %i and %d is that when used with scanf(), then %d always expects a decimal integer, whereas %i recognizes the 0 and 0x prefixes as octal and hexadecimal, but no sane programmer uses scanf() anyway so this should not be a concern.)
You could read the entire input line from scanner, then split the line by , then you have a String[], parse each number into int[] with index one to one matching…(assuming valid input and no NumberFormatExceptions) like As YoYo’s answer suggests, the above can be achieved more concisely in Java 8: To handle invalid input … Read more
double supports Infinity Add New Post Add titleHow to implement infinity in Java? double supports Infinitydouble inf = Double.POSITIVE_INFINITY; System.out.println(inf + 5); System.out.println(inf – inf); // same as Double.NaN System.out.println(inf * -1); // same as Double.NEGATIVE_INFINITY printsInfinity NaN -Infinity prints note: Infinity – Infinity is Not A Number.
You just need to cast at least one of the operands to a float: or or (unnecessary)
I used the idea from Kerry’s answer, but simplified it since I was just looking for something simple for my specific purpose. Here is what I have: Show code snippet The regex uses 2 lookahead assertions: a positive one to look for any point in the string that has a multiple of 3 digits in … Read more
You can convert to String using Integer.toString() :