I’m dealing with a file with a linked list of lines with each node looking like this: and I’m writing a function that adds spaces at the beginning of the lines found in the variable text, by calling functions like linelist_ptr->text.insert(0,1,’\t’); The program compiles, but when I run it I get this error: Any ideas?
The problem lies here: When you delete first, but then try to access first->next. Cache first->next into a temp variable of type node*, then do delete first to fix this:
You can also take a look at llist python package, which provides some useful features that deque does not. There are not only doubly linked lists, but also single linked lists data structure in that package. IMHO, one of the biggest advantages of this package is the ability to store a reference to the llist elements.
The problem is here: Basically, when you free temp2, you free first, not the memory allocated here: , which remains a memory leak, because after the assignment it can’t be freed anymore. Also, your code has probably some more problems (one is that you shouldn’t use fflush on an input stream), but without some more details, it’s … Read more
You have to be careful with Step 1 and part of Step 2. Step 1 should allocate a new node and use that as the head. In Step 2, the part about next = v.next, unless your intention is to make a shallow copy, is incorrect. When you copy a container such as a linked list, you … Read more
Why not do it much much simpler – with an elegant while-loop instead of trying to carefully analyze whether that overcompilcated for-loop is correct?
It’s easier to store data of different sizes in a linked list. An array assumes every element is exactly the same size. As you mentioned, it’s easier for a linked list to grow organically. An array’s size needs to be known ahead of time, or re-created when it needs to grow. Shuffling a linked list … Read more
The short answer to this is that, Python is a pass-by-object-reference language, not pass-by-reference as implied in the question. It means that: result and result_tail are two variables that happen to point at the same value Mutation / Changing of the underlying value (result_tail.next = ListNode(1)) will affect the value shown by result However, assigning / pointing the variable result_tail to … Read more
Yes, LinkedList is a doubly linked list, as the Javadoc mentions : Doubly-linked list implementation of the List and Deque interfaces. Implements all optional list operations, and permits all elements (including null). All of the operations perform as could be expected for a doubly-linked list. Operations that index into the list will traverse the list … Read more