Ignoring NaNs with str.containsv
There’s a flag for that: See the str.replace docs: na : default NaN, fill value for missing values. So you can do the following:
There’s a flag for that: See the str.replace docs: na : default NaN, fill value for missing values. So you can do the following:
You can use the package sklearn and its associated preprocessing utilities to normalize the data. For more information look at the scikit-learn documentation on preprocessing data: scaling features to a range.
To select the ith row, use iloc: To select the ith value in the Btime column you could use: There is a difference between df_test[‘Btime’].iloc[0] (recommended) and df_test.iloc[0][‘Btime’]: DataFrames store data in column-based blocks (where each block has a single dtype). If you select by column first, a view can be returned (which is quicker than returning a copy) and the original dtype is preserved. In … Read more
I think you can use SeriesGroupBy.nunique: Another solution with unique, then create new df by DataFrame.from_records, reshape to Series by stack and last value_counts:
NOTE: pd.convert_objects has now been deprecated. You should use pd.Series.astype(float) or pd.to_numeric as described in other answers. This is available in 0.11. Forces conversion (or set’s to nan) This will work even when astype will fail; its also series by series so it won’t convert say a complete string column
You can use the package sklearn and its associated preprocessing utilities to normalize the data. For more information look at the scikit-learn documentation on preprocessing data: scaling features to a range.
I believe you can use the append method to keep their indexes just dont use the ignore_index keyword …
To change the labels for Pandas df.plot() use ax.legend([…]): Another approach is to do the same by plt.legend([…]):
I believe need change: to: because old pandas version code below pandas 0.18.0
You can use df.loc[i], where the row with index i will be what you specify it to be in the dataframe.