Regex – Does not contain certain Characters
The caret in the character class ([^) means match anything but, so this means, beginning of string, then one or more of anything except < and >, then the end of the string.
The caret in the character class ([^) means match anything but, so this means, beginning of string, then one or more of anything except < and >, then the end of the string.
I need a way of searching a file using grep via a regular expression from the Unix command line. For example when I type in the command line: I need the regular expression ‘RE’ to be searched in the file and print out the matching lines. Here’s the code I have: But when I enter a word … Read more
. is any char, * means repeated zero or more times.
str.replace() v2|v3 does not recognize regular expressions. To perform a substitution using a regular expression, use re.sub() v2|v3. For example: In a loop, it would be better to compile the regular expression first:
1066 Regular expressions are used for Pattern Matching. To use in Excel follow these steps: Step 1: Add VBA reference to “Microsoft VBScript Regular Expressions 5.5” Select “Developer” tab (I don’t have this tab what do I do?) Select “Visual Basic” icon from ‘Code’ ribbon section In “Microsoft Visual Basic for Applications” window select “Tools” from … Read more
You can use str.isalnum: If you insist on using regex, other solutions will do fine. However note that if it can be done without using a regular expression, that’s the best way to go about it.
This can be done without regex: You can use str.isalnum: If you insist on using regex, other solutions will do fine. However note that if it can be done without using a regular expression, that’s the best way to go about it.
As comments and other answers indicate your question may not be quite explicit enough. Taking it at face value, if you just want to replace double quotes (“) you should use str_replace()
Yes, you can. That should work. . = any char except newline \. = the actual dot character .? = .{0,1} = match any char except newline zero or one times .* = .{0,} = match any char except newline zero or more times .+ = .{1,} = match any char except newline one or more times
Use the beginning and end anchors. Use “^\d+$” if you need to match more than one digit. Note that “\d” will match [0-9] and other digit characters like the Eastern Arabic numerals ٠١٢٣٤٥٦٧٨٩. Use “^[0-9]+$” to restrict matches to just the Arabic numerals 0 – 9. If you need to include any numeric representations other than just digits (like decimal values for starters), then … Read more