You can convert char to int and viceversa easily because for the machine an int and a char are the same, 8 bits, the only difference comes when they have to be shown in screen, if the number is 65 and is saved as a char, then it will show ‘A’, if it’s saved as … Read more
If your string contains exactly one character the simplest way to convert it to a character is probably to call the charAt method:
No, there’s no direct not operator. At least not the way you hope for. You can use a zero-width negative lookahead, however: The (?!…) part means “only match if the text following (hence: lookahead) this doesn’t (hence: negative) match this. But it doesn’t actually consume the characters it matches (hence: zero-width). There are actually 4 combinations of lookarounds with 2 axes: lookbehind / lookahead : … Read more
You can use Character.toString(char). Note that this method simply returns a call to String.valueOf(char), which also works. As others have noted, string concatenation works as a shortcut as well: But this compiles down to: which is less efficient because the StringBuilder is backed by a char[] (over-allocated by StringBuilder() to 16), only for that array to be defensively copied by the resulting String. String.valueOf(char) “gets in … Read more
Since ES6, you can use template literals: Expand snippet P.S. Note the use of backticks: “.
You don’t need “string” in your call to wordLengthFunction(). int wordLength = wordLengthFunction(string word); should be int wordLength = wordLengthFunction(word);
EDIT: As pointed out in the comment, itoa() is not a standard, so better use sprintf() approach suggested in the rivaling answer! You can use itoa() function to convert your integer value to a string. Here is an example: If you want to output your structure into a file there is no need to convert … Read more
Simplest way I can think of doing it is: For safety, you might prefer: or could be in this fashion:
The simplest way would be to use the native Number function: If that doesn’t work for you, then there are the parseInt, unary plus, parseFloat with floor, and Math.round methods. parseInt: unary plus if your string is already in the form of an integer: if your string is or might be a float and you want an integer: or, if you’re going … Read more
Try this: or better yet: Also, since Int32.TryParse returns a bool you can use its return value to make decisions about the results of the parsing attempt: If you are curious, the difference between Parse and TryParse is best summed up like this: The TryParse method is like the Parse method, except the TryParse method does not throw an exception if the conversion … Read more