C++11 introduces std::stoi (and variants for each numeric type) and std::to_string, the counterparts of the C atoi and itoa but expressed in term of std::string. is therefore the shortest way I can think of. You can even omit naming the type, using the auto keyword: Note: see [string.conversions] (21.5 in n3242)
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In C++11 there are some nice new convert functions from std::string to a number type. So instead of you can use where str is your number as std::string. There are version for all flavours of numbers: long stol(string), float stof(string), double stod(string),… see http://en.cppreference.com/w/cpp/string/basic_string/stol
Simplest way I can think of doing it is: For safety, you might prefer: or could be in this fashion:
You need to replace() in this use case, not strip() strip(): string.strip(s[, chars]) Return a copy of the string with leading and trailing characters removed. If chars is omitted or None, whitespace characters are removed. If given and not None, chars must be a string; the characters in the string will be stripped from the … Read more
lexicographical order is alphabetical order. The other type is numerical ordering. Consider the following values, Those values are in lexicographical order. 10 comes after 2 in numerical order, but 10 comes before 2 in “alphabetical” order.
This question’s answers are a community effort. Edit existing answers to improve this post. It is not currently accepting new answers or interactions. How do I read every line of a file in Python and store each line as an element in a list? I want to read the file line by line and append … Read more
Don’t modify strings. Work with them as lists; turn them into strings only when needed. Python strings are immutable (i.e. they can’t be modified). There are a lot of reasons for this. Use lists until you have no choice, only then turn them into strings.
Strings in python are immutable, so you cannot treat them as a list and assign to indices. Use .replace() instead: If you need to replace only certain semicolons, you’ll need to be more specific. You could use slicing to isolate the section of the string to replace in: That’ll replace all semi-colons in the first 10 characters of the … Read more
There are multiple ways: String.valueOf(number) (my preference) “” + number (I don’t know how the compiler handles it, perhaps it is as efficient as the above) Integer.toString(number)