The most straightforward answer is: The difference here is that will place Hello world in the read-only parts of the memory and making s a pointer to that, making any writing operation on this memory illegal. While doing: puts the literal string in read-only memory and copies the string to newly allocated memory on the … Read more
The Character class of Java API has various functions you can use. You can convert your char to lowercase at both sides: There are also a methods you can use to verify if the letter is uppercase or lowercase:
You need to include header <iomanip> for std::setprecision and <limits> for std::numeric_limits. These references tell you which header to include.
I am new to python and I have a string that looks like this Temp = “‘, ‘/1412311.2121\n“ my desired output is just getting the numbers and decimal itself.. so im looking for as the output.. trying to get rid of the ‘, ‘/\n in the string.. I have tried Temp.strip(“\n”) and Temp.rstrip(“\n”) for trying … Read more
You can use %zd as the format specifier in a scanf-type approach. Or use a std::stringstream which will have an overloaded >> to size_t.
This part of the code is suspicious: Your array has length 9, so the valid indices in it range from 0, 1, 2, …, 8. On iteration 8, the indicated line will try to read array index 9, which isn’t valid. This results in undefined behavior, which in your case is a misleading error message … Read more
The format specifiers for String formatting in Swift are the same as those in Objective-C NSString format, itself identical to those for CFString format and are buried deep in the archives of Apple Documentation (same content for both pages, both originally from year 2002 or older): https://developer.apple.com/library/archive/documentation/CoreFoundation/Conceptual/CFStrings/formatSpecifiers.html https://developer.apple.com/library/archive/documentation/Cocoa/Conceptual/Strings/Articles/formatSpecifiers.html But this documentation page itself is incomplete, … Read more
char* is a pointer to char, char ** is a pointer to a pointer to char. char *ptr; does NOT allocate memory for characters, it allocates memory for a pointer to char. char arr[10]; allocates 10 characters and arr holds the address of the first character. (though arr is NOT a pointer (not char *) … Read more
The error is telling you that the two return values from strconv.Atoi (int and error) are used in a single value context (the assignment to time). Change the code to: Use the blank identifier to ignore the error return value: