How do I erase an element from std::vector<> by index?
To delete a single element, you could do: Or, to delete more than one element at once:
To delete a single element, you could do: Or, to delete more than one element at once:
For next examples assumed that you use C++11. Example with ranged-based for loops: You should use const auto &attack depending on the behavior of makeDamage(). You can use std::for_each from standard library + lambdas: If you are uncomfortable using std::for_each, you can loop over m_attack using iterators: Use m_attack.cbegin() and m_attack.cend() to get const iterators.
You need to make use of the begin and end method of the vector class, which return the iterator referring to the first and the last element respectively.
You can just use table(): Then you can subset it: Or convert it into a data.frame if you’re more comfortable working with that:
Checking if v contains the element x: Checking if v contains elements (is non-empty):
Simplest solution Use numpy.dot or a.dot(b). See the documentation here. This occurs because numpy arrays are not matrices, and the standard operations *, +, -, / work element-wise on arrays. Note that while you can use numpy.matrix (as of early 2021) where * will be treated like standard matrix multiplication, numpy.matrix is deprecated and may … Read more
If you have a C++11 compiler, I would suggest using a range-based for-loop (see below); or else use an iterator. But you have several options, all of which I will explain in what follows. range-based for-loop (C++11) In C++11 (and later) you can use the new range-based for-loop, which looks like this: The type char … Read more
You can use std::find from <algorithm>: This returns a bool (true if present, false otherwise). With your example:
As it is, both dimensions of your vector are 0. Instead, initialize the vector as this: This will give you a matrix of dimensions RR * CC with all elements set to 0.
One method would be to use the array to initialize the vector