The best and most efficient way is to catch the “table not found” exception: this avoids the overhead of checking if the table exists twice; and doesn’t suffer from the problem that if the DROP fails for some other reason (that might be important) the exception is still raised to the caller: ADDENDUM For reference, … Read more
I have MS Sql server 2012, and Office 2013. This seems to be very finicky, so you may have to adjust to your particular versions. Download the Microsoft.ACE.OLEDB.12.0 for Windows, 64 bit version found here: https://www.microsoft.com/en-us/download/details.aspx?id=13255 Install it on your server. Check the user running SQL Server and make sure that user has access to the … Read more
If you want to get this out of your table using SQL, take a look at the following functions that will help you: SUBSTRING and CHARINDEX. You can use those to trim your entries. A possible query will look like this (where col is the name of the column that contains your image directories: Bit of an ugly beast. It … Read more
phpPgAdmin might work for you, if you’re already familiar with phpMyAdmin. Please note that development of phpPgAdmin has moved to github per this notice but the SourceForge link above is for historical / documentation purposes. But really there are dozens of tools that can do this.
One option is to put the subquery in a LEFT JOIN: Perhaps a better option would be to use SUM with CASE: SQL Fiddle Demo with both
Let’s say for instance you want to get a list of all your customers: And let’s assume that each Customer object has a reference to its set of Orders, and that each Order has references to LineItems which may also reference a Product. As you can see, selecting a top-level object with many related entities … Read more
You could use NOT IN
Add a WHERE clause
You are dropping it, then creating it, then trying to create it again by using SELECT INTO. Change to: In MS SQL Server you can create a table without a CREATE TABLE statement by using SELECT INTO
I think what you are asking for will work by joining the Initial table to both Option_A and Option_B using LEFT JOIN, which will produce something like this: Example code: Once you have done this, you ‘ignore’ the set of NULLS. The additional trick here is in the SELECT line, where you need to decide … Read more