Alternate table row color using CSS?

$(document).ready(function()
{
  $("tr:odd").css({
    "background-color":"#000",
    "color":"#fff"});
});

tbody td{
  padding: 30px;
}

tbody tr:nth-child(odd){
  background-color: #4C8BF5;
  color: #fff;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table border="1">
<tbody>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>5</td>
<td>6</td>
<td>7</td>
<td>8</td>
</tr>
<tr>
<td>9</td>
<td>10</td>
<td>11</td>
<td>13</td>
</tr>
</tbody>
</table>

Expand snippet

There is a CSS selector, really a pseudo-selector, called nth-child. In pure CSS you can do the following:

tr:nth-child(even)
    background-color: #000000;
}

Note: No support in IE 8.

Or, if you have jQuery:

$(document).ready(function()
{
    $("tr:even").css("background-color", "#000000");
});