How to convert an integer to a character array using C

Make use of the log10 function to determine the number of digits and do like below:

char * toArray(int number)
{
    int n = log10(number) + 1;
    int i;
    char *numberArray = calloc(n, sizeof(char));
    for (i = n-1; i >= 0; --i, number /= 10)
    {
        numberArray[i] = (number % 10) + '0';
    }
    return numberArray;
}

Or the other option is sprintf(yourCharArray,"%ld", intNumber);