Yes, it is possible: To chain to a particular superclass constructor instead of one in the same class, use super instead of this. Note that you can only chain to one constructor, and it has to be the first statement in your constructor body. See also this related question, which is about C# but where the same principles apply.
TypeScript allows you to declare overloads but you can only have one implementation and that implementation must have a signature that is compatible with all overloads. In your example, this can easily be done with an optional parameter as in, or two overloads with a more general constructor as in, See in Playground
Defining the body of the constructor INSIDE the class has the same effect of placing the function OUTSIDE the class with the “inline” keyword. In both cases it’s a hint to the compiler. An “inline” function doesn’t necessarily mean the function will be inlined. That depends on the complexity of the function and other rules.
Creates an object of type Foo in dynamic memory. foo1 points to it. Normally, you wouldn’t use raw pointers in C++, but rather a smart pointer. If Foo was a POD-type, this would perform value-initialization (it doesn’t apply here). Identical to before, because Foo is not a POD type. Creates a Foo object called foo3 in automatic storage. Uses copy-initialization to create a Foo object called foo4 in automatic storage. Uses Bar‘s … Read more
Note: Cloning the lists, isn’t the same as cloning the elements in the list. None of these approaches work the way you want them to: The approaches above will fill people such that it contains the same elements as other.people. However, you don’t want it to contain the same elements. You want to fill it with clones of … Read more
Try adding square brackets after new MyClass and a semi-colon at the end
Modify your constructor to the following so that it calls the base class constructor properly: Note that a constructor is not something that you can call anytime within a method. That’s the reason you’re getting errors in your call in the constructor body.
Add this to your class: Please understand that default no-argument constructor is provided only if no other constructor is written If you write any constructor, then compiler does not provided default no-arg constructor. You have to specify one.
You can not initialize tst_ where you declare it. This can only be done for static const primitive types. Instead you will need to have a constructor for class test1. EDIT: below, you will see a working example I did in ideone.com. Note a few changes I did. First, it is better to have the … Read more
There is no way to explicitly specify the template arguments when calling a constructor template, so they have to be deduced through argument deduction. This is because if you say: The <int> is the template argument list for the type Foo, not for its constructor. There’s nowhere for the constructor template’s argument list to go. … Read more