Compiler error: “initializer element is not a compile-time constant”

When you define a variable outside the scope of a function, that variable’s value is actually written into your executable file. This means you can only use a constant value. Since you don’t know everything about the runtime environment at compile time (which classes are available, what is their structure, etc.), you cannot create objective … Read more

How to initialize array to 0 in C?

Global variables and static variables are automatically initialized to zero. If you have simply at global scope it will be all zeros at runtime. But actually there is a shorthand syntax if you had a local array. If an array is partially initialized, elements that are not initialized receive the value 0 of the appropriate type. You … Read more

Error “initializer element is not constant” when trying to initialize variable with const

In C language, objects with static storage duration have to be initialized with constant expressions, or with aggregate initializers containing constant expressions. A “large” object is never a constant expression in C, even if the object is declared as const. Moreover, in C language, the term “constant” refers to literal constants (like 1, ‘a’, 0xFF and so on), enum members, and results of … Read more

“error: assignment to expression with array type error” when I assign a struct field (C)

You are facing issue in because, in the LHS, you’re using an array type, which is not assignable. To elaborate, from C11, chapter §6.5.16 assignment operator shall have a modifiable lvalue as its left operand. and, regarding the modifiable lvalue, from chapter §6.3.2.1 A modifiable lvalue is an lvalue that does not have array type, […] You need to use strcpy() to copy … Read more