Interesting answers but the docs say differently: Use the GetNumericValue methods to convert a Char object that represents a number to a numeric value type. Use Parse and TryParse to convert a character in a string into a Char object. Use ToString to convert a Char object to a String object. http://msdn.microsoft.com/en-us/library/system.char.aspx
You’ll get that error once your numbers are greater than sys.maxsize: You can confirm this by checking: To take numbers with larger precision, don’t pass an int type which uses a bounded C integer behind the scenes. Use the default float:
int variables can’t be null If a null is to be converted to int, then it is the converter which decides whether to set 0, throw exception, or set another value (like Integer.MIN_VALUE). Try to plug your own converter.
An int is not null, it may be 0 if not initialized. If you want an integer to be able to be null, you need to use Integer instead of int. Besides the statement if(person.equals(null)) can’t be true, because if person is null, then a NullPointerException will be thrown. So the correct expression is if (person == null)
You’ll get that error once your numbers are greater than sys.maxsize: You can confirm this by checking: To take numbers with larger precision, don’t pass an int type which uses a bounded C integer behind the scenes. Use the default float:
Between int32 and int32_t, (and likewise between int8 and int8_t) the difference is pretty simple: the C standard defines int8_t and int32_t, but does not define anything named int8 or int32 — the latter (if they exist at all) is probably from some other header or library (most likely predates the addition of int8_t and int32_t in C99). Plain int is quite a bit different from the others. Where int8_t and int32_t each have a specified size, int can be … Read more
Use a DecimalFormatter: Will give you “0.99”. You can add or subtract 0 on the right side to get more or less decimals. Or use ‘#’ on the right to make the additional digits optional, as in with #.## (0.30) would drop the trailing 0 to become (0.3).
Use a DecimalFormatter: Will give you “0.99”. You can add or subtract 0 on the right side to get more or less decimals. Or use ‘#’ on the right to make the additional digits optional, as in with #.## (0.30) would drop the trailing 0 to become (0.3).
“N/A” is not an integer. It must throw NumberFormatException if you try to parse it to an integer. Check before parsing or handle Exception properly. Exception Handlingtry{ int i = Integer.parseInt(input); } catch(NumberFormatException ex){ // handle your exception … } or – Integer pattern matching –
Math.ceil() is the correct function to call. I’m guessing a is an int, which would make a / 100 perform integer arithmetic. Try Math.ceil(a / 100.0) instead. Outputs: