First of all, you use the data type int, which cannot hold fractional values (and will implicitly round them towards zero, even before the function is ever called.) You should use double instead, since this is the proper datatype for fractional numbers. You would also want to use the ceil(x) function, which gives the nearest whole number larger than or … Read more
Which is the best efficient way to round up a number and then truncate it (remove decimal places after rounding up)? for example if decimal is above 0.5 (that is, 0.6, 0.7, and so on), I want to round up and then truncate (case 1). Otherwise, I would like to truncate (case 2)
If you explicitly cast double to int, the decimal part will be truncated. For example: Moreover, you may also use Math.floor() method to round values in case you want double value in return.
The following should work. After reading your question, I’m not exactly sure what you want 100 to return. For this 100 returns 100. This gives the following results:
I have these two variables Then I did this expression but I end up with 27.0. In fact I have many other variables and when I use them in the expression I always get a 0 in the tenth’s place.
Use Math.Ceiling()
You can use Math.ceil() method. See JavaDoc link: https://docs.oracle.com/javase/10/docs/api/java/lang/Math.html#ceil(double) From the docs: ceil Returns the smallest (closest to negative infinity) double value that is greater than or equal to the argument and is equal to a mathematical integer. Special cases: If the argument value is already equal to a mathematical integer, then the result is the same as … Read more
You can use negative numbers to round integers: Thus if you need only most significant digit: You’ll probably have to take care of turning float to integer if it’s bigger than 1.