In fibonacci sequence each item is the sum of the previous two. So, you wrote a recursive algorithm. So, Now you already know fibonacci(1)==1 and fibonacci(0) == 0. So, you can subsequently calculate the other values. Now, And from fibonacci sequence 0,1,1,2,3,5,8,13,21…. we can see that for 5th element the fibonacci sequence returns 5. like … Read more
What the traceback error is pointing out is the misuse of for statement: for i in Updt(): for in python 3 is as follows: “Python’s for statement iterates over the items of any sequence (a list or a string), in the order that they appear in the sequence.” (source: python 3.3 documentation, section 4: More … Read more
Loop over the file to read lines: File objects are iterable and yield lines until EOF. Using the file object as an iterable uses a buffer to ensure performant reads. You can do the same with the stdin (no need to use raw_input(): To complete the picture, binary reads can be done with: where chunk … Read more
You want: sizeof gives you the size of the pointer, not the string. However, it would have worked if you had declared the pointer as an array: but if you pass the array to function, that too will decay to a pointer. For strings it’s best to always use strlen. And note what others have … Read more
Use forEach its a built-in array function. Array.forEach():
and so on you can substitute the value of T(n-1) and T(n-2) in T(n) to get a general idea of the pattern. For base case: => k = n – 1substitute in (1) Which you can see is of Order n2 => O(n2).
For terseness, Let F(x) be the recursive Fibonacci So your are calling F(8) twice, F(7) 3 times, F(6) 5 times, F(5) 7 times.. and so on So with larger inputs, the tree gets bigger and bigger.
I use a for loop to iterate the string and use charAt() to get each character to examine it. Since the String is implemented with an array, the charAt() method is a constant time operation. That’s what I would do. It seems the easiest to me. As far as correctness goes, I don’t believe that exists here. It is … Read more
C implementation of your bonus question, in three lines: