error: incompatible types: char cannot be converted to String – Java
You can easily convert the char to String. So in your case:
java
Creating Jar with Intellij 2016 – No main manifest attribute
I was stucked with the same problem with maven build. When you are creating the artifact from project structure settings (ctrl+alt+shift+S), you have to change manifest directory: change java to resources I have also used the option extract to the target JAR, and it’s working well. EDIT You can find a detailed step-by-step, an other … Read more
java – How to handle array:Exception in thread “main” java.lang.ArrayIndexOutOfBoundsException: 3
should be since you can have length – 1 number of comparisons.
Shuffle a deck of cards in Java
Simply use a new array for the shuffled cards and fill it using random cards removed from the prior array. Or just use Collections.shuffle():
How to clear console in Java – Eclipse
It depends on your console but if it supports ANSI escape sequences, then try this.. Also, you can print multiple end of lines (“\n”) and simulate the clear screen. At the end clear, at most in the unix shell, not removes the previous content, only moves it up and if you make scroll down can … Read more
How to create a popup window in javafx
I want to create a popup window in a JavaFX application. Give me some ideas. When I click on Check button it opens the popup window. How to do it?
Regular Expressions on Punctuation
I would try a character class regex similar to Add whatever characters you wish to match inside the []s. Be careful to escape any characters that might have a special meaning to the regex parser. You then have to iterate through the matches by using Matcher.find() until it returns false.
Creating random numbers with no duplicates
The simplest way would be to create a list of the possible numbers (1..20 or whatever) and then shuffle them with Collections.shuffle. Then just take however many elements you want. This is great if your range is equal to the number of elements you need in the end (e.g. for shuffling a deck of cards). … Read more
java.lang.ArrayIndexOutOfBoundsException: 4 Error
All of your calls to arrayCharToInt[x+1] are going to go out of bounds on the last iteration of the loop they’re in (for example, if arrayCharToInt.length equals 5, the highest that x is going to go is 4. But then x+1 equals 5, which is out of bounds for an array with five cells). You’ll need to put in some sort of if( x … Read more