CAUSE There could be multiple reasons for this error. jQuery DataTables library is missing. jQuery library is loaded after jQuery DataTables. Multiple versions of jQuery library is loaded. SOLUTION Include only one version of jQuery library version 1.7 or newer before jQuery DataTables. For example: See jQuery DataTables: Common JavaScript console errors for more information … Read more
To break a $.each or $(selector).each loop, you have to return false in the loop callback. Returning true skips to the next iteration, equivalent to a continue in a normal loop.
This type of error mean that your container variable fileis not defined. You should use console.log at different places to see what is defined and what is not (your files array, etc.) Also : Will be undefined for the last x value, because the last element of an array is at array.length – 1and not array.length, that gives you an undefined value … Read more
Since text() gets the value, and text( “someValue” ) sets the value, you just place one inside the other. Would be the equivalent of doing: EDIT: I hope I understood the question correctly. I’m assuming $mylabel is referencing a DOM element in a jQuery object, and the string is in the content of the element. If the string is in some … Read more
Using jQuery You can set the class (regardless of what it was) by using .attr(), like this: If you want to add a class, use .addclass() instead, like this: Or a short way to swap classes using .toggleClass(): Here’s the full list of jQuery methods specifically for the class attribute.
You need to use the event delegation syntax of .on() here. Change: to jsFiddle example
If you want to do for several images then: Use:
I created this fiddle to and it works well as per my requirements: Fiddle However, when I use the same in my application I get an error in the browser console saying Cannot read property ‘aDataSort’ of undefined In my application, the javascript reads something like as below: I have checked the controller output…it works … Read more
document.getElementsByClassName() returns a nodeList, not an element! So it should be : and as you probably have more .hidden elements, and only want the one inside the current .box (which would be this in the event handler) but why not jQuery
Samuel Liew is right. sometimes jquery conflict with the other jqueries. to solve this problem you need to put them in such a order that they may not conflict with each other. do one thing: open your application in google chrome and inspect bottom right corner with red marked errors. which kind of error that … Read more